7a-4-4a=3(3a+7)+23

Solution for 7a-4-4a=3(3a+7)+23 equation:

7a-4-4a=3(3a+7)+23

We move all terms to the left:

7a-4-4a-(3(3a+7)+23)=0

We add all the numbers together, and all the variables

3a-(3(3a+7)+23)-4=0


We calculate terms in parentheses: -(3(3a+7)+23), so:

3(3a+7)+23

We multiply parentheses

9a+21+23

We add all the numbers together, and all the variables

9a+44

Back to the equation:

-(9a+44)


We get rid of parentheses

3a-9a-44-4=0

We add all the numbers together, and all the variables

-6a-48=0

We move all terms containing a to the left, all other terms to the right

-6a=48

a=48/-6

a=-8