7a-4-4a=3(3a+7)=23

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Solution for 7a-4-4a=3(3a+7)=23 equation: 



7a-4-4a=3(3a+7)=23

We move all terms to the left:

7a-4-4a-(3(3a+7))=0

We add all the numbers together, and all the variables

3a-(3(3a+7))-4=0



We calculate terms in parentheses: -(3(3a+7)), so:

3(3a+7)

We multiply parentheses

9a+21

Back to the equation:

-(9a+21)



We get rid of parentheses

3a-9a-21-4=0

We add all the numbers together, and all the variables

-6a-25=0

We move all terms containing a to the left, all other terms to the right

-6a=25

a=25/-6

a=-4+1/6

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