7a2+10a-3a-2a2=0

Solution for 7a2+10a-3a-2a2=0 equation:

7a^2+10a-3a-2a^2=0

We add all the numbers together, and all the variables

5a^2+7a=0

a = 5; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·5·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*5}=\frac{-14}{10}
=-1+2/5
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*5}=\frac{0}{10}
=0
$