7b-3b+7=3(b-4)-9b

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Solution for 7b-3b+7=3(b-4)-9b equation: 



7b-3b+7=3(b-4)-9b

We move all terms to the left:

7b-3b+7-(3(b-4)-9b)=0

We add all the numbers together, and all the variables

4b-(3(b-4)-9b)+7=0



We calculate terms in parentheses: -(3(b-4)-9b), so:

3(b-4)-9b

We add all the numbers together, and all the variables

-9b+3(b-4)

We multiply parentheses

-9b+3b-12

We add all the numbers together, and all the variables

-6b-12

Back to the equation:

-(-6b-12)



We get rid of parentheses

4b+6b+12+7=0

We add all the numbers together, and all the variables

10b+19=0

We move all terms containing b to the left, all other terms to the right

10b=-19

b=-19/10

b=-1+9/10

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