7b-4(3-b)=3(b+12)

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Solution for 7b-4(3-b)=3(b+12) equation: 



7b-4(3-b)=3(b+12)

We move all terms to the left:

7b-4(3-b)-(3(b+12))=0

We add all the numbers together, and all the variables

7b-4(-1b+3)-(3(b+12))=0

We multiply parentheses

7b+4b-(3(b+12))-12=0



We calculate terms in parentheses: -(3(b+12)), so:

3(b+12)

We multiply parentheses

3b+36

Back to the equation:

-(3b+36)



We add all the numbers together, and all the variables

11b-(3b+36)-12=0

We get rid of parentheses

11b-3b-36-12=0

We add all the numbers together, and all the variables

8b-48=0

We move all terms containing b to the left, all other terms to the right

8b=48

b=48/8

b=6

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