7b-7(b-4)=8b+6(4-b)

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Solution for 7b-7(b-4)=8b+6(4-b) equation: 



7b-7(b-4)=8b+6(4-b)

We move all terms to the left:

7b-7(b-4)-(8b+6(4-b))=0

We add all the numbers together, and all the variables

7b-7(b-4)-(8b+6(-1b+4))=0

We multiply parentheses

7b-7b-(8b+6(-1b+4))+28=0



We calculate terms in parentheses: -(8b+6(-1b+4)), so:

8b+6(-1b+4)

We multiply parentheses

8b-6b+24

We add all the numbers together, and all the variables

2b+24

Back to the equation:

-(2b+24)



We add all the numbers together, and all the variables

-(2b+24)+28=0

We get rid of parentheses

-2b-24+28=0

We add all the numbers together, and all the variables

-2b+4=0

We move all terms containing b to the left, all other terms to the right

-2b=-4

b=-4/-2

b=+2

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