7c+2-4(2c+1)=3(c+3)

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Solution for 7c+2-4(2c+1)=3(c+3) equation: 



7c+2-4(2c+1)=3(c+3)

We move all terms to the left:

7c+2-4(2c+1)-(3(c+3))=0

We multiply parentheses

7c-8c-(3(c+3))-4+2=0



We calculate terms in parentheses: -(3(c+3)), so:

3(c+3)

We multiply parentheses

3c+9

Back to the equation:

-(3c+9)



We add all the numbers together, and all the variables

-1c-(3c+9)-2=0

We get rid of parentheses

-1c-3c-9-2=0

We add all the numbers together, and all the variables

-4c-11=0

We move all terms containing c to the left, all other terms to the right

-4c=11

c=11/-4

c=-2+3/4

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