7c+3(3c+5)=-113

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Solution for 7c+3(3c+5)=-113 equation:



7c+3(3c+5)=-113
We move all terms to the left:
7c+3(3c+5)-(-113)=0
We add all the numbers together, and all the variables
7c+3(3c+5)+113=0
We multiply parentheses
7c+9c+15+113=0
We add all the numbers together, and all the variables
16c+128=0
We move all terms containing c to the left, all other terms to the right
16c=-128
c=-128/16
c=-8

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