7c+3(5+c)=2(5c+2)+11

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Solution for 7c+3(5+c)=2(5c+2)+11 equation: 



7c+3(5+c)=2(5c+2)+11

We move all terms to the left:

7c+3(5+c)-(2(5c+2)+11)=0

We add all the numbers together, and all the variables

7c+3(c+5)-(2(5c+2)+11)=0

We multiply parentheses

7c+3c-(2(5c+2)+11)+15=0



We calculate terms in parentheses: -(2(5c+2)+11), so:

2(5c+2)+11

We multiply parentheses

10c+4+11

We add all the numbers together, and all the variables

10c+15

Back to the equation:

-(10c+15)



We add all the numbers together, and all the variables

10c-(10c+15)+15=0

We get rid of parentheses

10c-10c-15+15=0

We add all the numbers together, and all the variables

=0

c=0/1

c=0

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