7c+3(c-5)=2(c+3)-14

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Solution for 7c+3(c-5)=2(c+3)-14 equation:


Simplifying
7c + 3(c + -5) = 2(c + 3) + -14

Reorder the terms:
7c + 3(-5 + c) = 2(c + 3) + -14
7c + (-5 * 3 + c * 3) = 2(c + 3) + -14
7c + (-15 + 3c) = 2(c + 3) + -14

Reorder the terms:
-15 + 7c + 3c = 2(c + 3) + -14

Combine like terms: 7c + 3c = 10c
-15 + 10c = 2(c + 3) + -14

Reorder the terms:
-15 + 10c = 2(3 + c) + -14
-15 + 10c = (3 * 2 + c * 2) + -14
-15 + 10c = (6 + 2c) + -14

Reorder the terms:
-15 + 10c = 6 + -14 + 2c

Combine like terms: 6 + -14 = -8
-15 + 10c = -8 + 2c

Solving
-15 + 10c = -8 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
-15 + 10c + -2c = -8 + 2c + -2c

Combine like terms: 10c + -2c = 8c
-15 + 8c = -8 + 2c + -2c

Combine like terms: 2c + -2c = 0
-15 + 8c = -8 + 0
-15 + 8c = -8

Add '15' to each side of the equation.
-15 + 15 + 8c = -8 + 15

Combine like terms: -15 + 15 = 0
0 + 8c = -8 + 15
8c = -8 + 15

Combine like terms: -8 + 15 = 7
8c = 7

Divide each side by '8'.
c = 0.875

Simplifying
c = 0.875

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