7c+3-4c=3-3(c+4)

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Solution for 7c+3-4c=3-3(c+4) equation: 



7c+3-4c=3-3(c+4)

We move all terms to the left:

7c+3-4c-(3-3(c+4))=0

We add all the numbers together, and all the variables

3c-(3-3(c+4))+3=0



We calculate terms in parentheses: -(3-3(c+4)), so:

3-3(c+4)

determiningTheFunctionDomain
-3(c+4)+3

We multiply parentheses

-3c-12+3

We add all the numbers together, and all the variables

-3c-9

Back to the equation:

-(-3c-9)



We get rid of parentheses

3c+3c+9+3=0

We add all the numbers together, and all the variables

6c+12=0

We move all terms containing c to the left, all other terms to the right

6c=-12

c=-12/6

c=-2

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