7c-2(6c+8)=7-(11+11c)

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Solution for 7c-2(6c+8)=7-(11+11c) equation: 



7c-2(6c+8)=7-(11+11c)

We move all terms to the left:

7c-2(6c+8)-(7-(11+11c))=0

We add all the numbers together, and all the variables

7c-2(6c+8)-(7-(11c+11))=0

We multiply parentheses

7c-12c-(7-(11c+11))-16=0



We calculate terms in parentheses: -(7-(11c+11)), so:

7-(11c+11)

determiningTheFunctionDomain
-(11c+11)+7

We get rid of parentheses

-11c-11+7

We add all the numbers together, and all the variables

-11c-4

Back to the equation:

-(-11c-4)



We add all the numbers together, and all the variables

-5c-(-11c-4)-16=0

We get rid of parentheses

-5c+11c+4-16=0

We add all the numbers together, and all the variables

6c-12=0

We move all terms containing c to the left, all other terms to the right

6c=12

c=12/6

c=2

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