7c-3-4c=3(c-1)

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Solution for 7c-3-4c=3(c-1) equation:


Simplifying
7c + -3 + -4c = 3(c + -1)

Reorder the terms:
-3 + 7c + -4c = 3(c + -1)

Combine like terms: 7c + -4c = 3c
-3 + 3c = 3(c + -1)

Reorder the terms:
-3 + 3c = 3(-1 + c)
-3 + 3c = (-1 * 3 + c * 3)
-3 + 3c = (-3 + 3c)

Add '3' to each side of the equation.
-3 + 3 + 3c = -3 + 3 + 3c

Combine like terms: -3 + 3 = 0
0 + 3c = -3 + 3 + 3c
3c = -3 + 3 + 3c

Combine like terms: -3 + 3 = 0
3c = 0 + 3c
3c = 3c

Add '-3c' to each side of the equation.
3c + -3c = 3c + -3c

Combine like terms: 3c + -3c = 0
0 = 3c + -3c

Combine like terms: 3c + -3c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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