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7c-5=2(2+2c)
We move all terms to the left:
7c-5-(2(2+2c))=0
We add all the numbers together, and all the variables
7c-(2(2c+2))-5=0
We calculate terms in parentheses: -(2(2c+2)), so:We get rid of parentheses
2(2c+2)
We multiply parentheses
4c+4
Back to the equation:
-(4c+4)
7c-4c-4-5=0
We add all the numbers together, and all the variables
3c-9=0
We move all terms containing c to the left, all other terms to the right
3c=9
c=9/3
c=3
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