7c=4(2c+15)

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Solution for 7c=4(2c+15) equation: 



7c=4(2c+15)

We move all terms to the left:

7c-(4(2c+15))=0



We calculate terms in parentheses: -(4(2c+15)), so:

4(2c+15)

We multiply parentheses

8c+60

Back to the equation:

-(8c+60)



We get rid of parentheses

7c-8c-60=0

We add all the numbers together, and all the variables

-1c-60=0

We move all terms containing c to the left, all other terms to the right

-c=60

c=60/-1

c=-60

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