7cos(x)+cos(2x)-3=0

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Solution for 7cos(x)+cos(2x)-3=0 equation:


Simplifying
7cos(x) + cos(2x) + -3 = 0

Multiply cos * x
7cosx + cos(2x) + -3 = 0

Remove parenthesis around (2x)
7cosx + cos * 2x + -3 = 0

Reorder the terms for easier multiplication:
7cosx + 2cos * x + -3 = 0

Multiply cos * x
7cosx + 2cosx + -3 = 0

Reorder the terms:
-3 + 7cosx + 2cosx = 0

Combine like terms: 7cosx + 2cosx = 9cosx
-3 + 9cosx = 0

Solving
-3 + 9cosx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '3' to each side of the equation.
-3 + 3 + 9cosx = 0 + 3

Combine like terms: -3 + 3 = 0
0 + 9cosx = 0 + 3
9cosx = 0 + 3

Combine like terms: 0 + 3 = 3
9cosx = 3

Divide each side by '9osx'.
c = 0.3333333333o-1s-1x-1

Simplifying
c = 0.3333333333o-1s-1x-1

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