7d-1/2(2d-4)=-5/4(d+4)

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Solution for 7d-1/2(2d-4)=-5/4(d+4) equation: 



7d-1/2(2d-4)=-5/4(d+4)

We move all terms to the left:

7d-1/2(2d-4)-(-5/4(d+4))=0



Domain of the equation: 2(2d-4)!=0

d∈R





Domain of the equation: 4(d+4))!=0

d∈R



We calculate fractions


7d+(-4dd/(2(2d-4)*4(d+4)))+(-(-10d2)/(2(2d-4)*4(d+4)))=0



We calculate terms in parentheses: +(-4dd/(2(2d-4)*4(d+4))), so:

-4dd/(2(2d-4)*4(d+4))

We multiply all the terms by the denominator


-4dd

Back to the equation:

+(-4dd)





We calculate terms in parentheses: +(-(-10d2)/(2(2d-4)*4(d+4))), so:

-(-10d2)/(2(2d-4)*4(d+4))

We add all the numbers together, and all the variables

-(-10d^2)/(2(2d-4)*4(d+4))

We multiply all the terms by the denominator


-(-10d^2)

We get rid of parentheses

10d^2

Back to the equation:

+(10d^2)



determiningTheFunctionDomain
10d^2+7d+(-4dd)=0

We get rid of parentheses

10d^2+7d-4dd=0

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