7d-2(d-3)+21=48-4(3-d)

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Solution for 7d-2(d-3)+21=48-4(3-d) equation: 



7d-2(d-3)+21=48-4(3-d)

We move all terms to the left:

7d-2(d-3)+21-(48-4(3-d))=0

We add all the numbers together, and all the variables

7d-2(d-3)-(48-4(-1d+3))+21=0

We multiply parentheses

7d-2d-(48-4(-1d+3))+6+21=0



We calculate terms in parentheses: -(48-4(-1d+3)), so:

48-4(-1d+3)

determiningTheFunctionDomain
-4(-1d+3)+48

We multiply parentheses

4d-12+48

We add all the numbers together, and all the variables

4d+36

Back to the equation:

-(4d+36)



We add all the numbers together, and all the variables

5d-(4d+36)+27=0

We get rid of parentheses

5d-4d-36+27=0

We add all the numbers together, and all the variables

d-9=0

We move all terms containing d to the left, all other terms to the right

d=9

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