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7h(6h+1)=0
We multiply parentheses
42h^2+7h=0
a = 42; b = 7; c = 0;
Δ = b2-4ac
Δ = 72-4·42·0
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-7}{2*42}=\frac{-14}{84} =-1/6 $$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+7}{2*42}=\frac{0}{84} =0 $
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