7h-35=3/2(h)

Solution for 7h-35=3/2(h) equation:

7h-35=3/2(h)

We move all terms to the left:

7h-35-(3/2(h))=0


Domain of the equation: 2h)!=0

h!=0/1

h!=0

h∈R


We add all the numbers together, and all the variables

7h-(+3/2h)-35=0

We get rid of parentheses

7h-3/2h-35=0

We multiply all the terms by the denominator


7h*2h-35*2h-3=0

Wy multiply elements

14h^2-70h-3=0

a = 14; b = -70; c = -3;
Δ = b2-4ac
Δ = -702-4·14·(-3)
Δ = 5068
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5068}=\sqrt{4*1267}=\sqrt{4}*\sqrt{1267}=2\sqrt{1267}$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-2\sqrt{1267}}{2*14}=\frac{70-2\sqrt{1267}}{28}
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+2\sqrt{1267}}{2*14}=\frac{70+2\sqrt{1267}}{28}
$