7h2-12h+5=0

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Solution for 7h2-12h+5=0 equation: 



7h^2-12h+5=0

a = 7; b = -12; c = +5;
Δ = b2-4ac
Δ = -122-4·7·5
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4}=2$


$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2}{2*7}=\frac{10}{14}
=5/7
$


$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2}{2*7}=\frac{14}{14}
=1
$

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