7h=-(2h-18)h=

Solution for 7h=-(2h-18)h= equation:

7h=-(2h-18)h=

We move all terms to the left:

7h-(-(2h-18)h)=0


We calculate terms in parentheses: -(-(2h-18)h), so:

-(2h-18)h

We multiply parentheses

-2h^2+18h

Back to the equation:

-(-2h^2+18h)


We get rid of parentheses

2h^2-18h+7h=0

We add all the numbers together, and all the variables

2h^2-11h=0

a = 2; b = -11; c = 0;
Δ = b2-4ac
Δ = -112-4·2·0
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$h_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-11)-11}{2*2}=\frac{0}{4}
=0
$
$h_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-11)+11}{2*2}=\frac{22}{4}
=5+1/2
$