7i(6-7i)=0

Solution for 7i(6-7i)=0 equation:

7i(6-7i)=0

We add all the numbers together, and all the variables

7i(-7i+6)=0

We multiply parentheses

-49i^2+42i=0

a = -49; b = 42; c = 0;
Δ = b2-4ac
Δ = 422-4·(-49)·0
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$i_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-42}{2*-49}=\frac{-84}{-98}
=6/7
$
$i_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+42}{2*-49}=\frac{0}{-98}
=0
$