7j(j+2)+3j(j+2)=

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Solution for 7j(j+2)+3j(j+2)= equation:


Simplifying
7j(j + 2) + 3j(j + 2) = 0

Reorder the terms:
7j(2 + j) + 3j(j + 2) = 0
(2 * 7j + j * 7j) + 3j(j + 2) = 0
(14j + 7j2) + 3j(j + 2) = 0

Reorder the terms:
14j + 7j2 + 3j(2 + j) = 0
14j + 7j2 + (2 * 3j + j * 3j) = 0
14j + 7j2 + (6j + 3j2) = 0

Reorder the terms:
14j + 6j + 7j2 + 3j2 = 0

Combine like terms: 14j + 6j = 20j
20j + 7j2 + 3j2 = 0

Combine like terms: 7j2 + 3j2 = 10j2
20j + 10j2 = 0

Solving
20j + 10j2 = 0

Solving for variable 'j'.

Factor out the Greatest Common Factor (GCF), '10j'.
10j(2 + j) = 0

Ignore the factor 10.

Subproblem 1

Set the factor 'j' equal to zero and attempt to solve: Simplifying j = 0 Solving j = 0 Move all terms containing j to the left, all other terms to the right. Simplifying j = 0

Subproblem 2

Set the factor '(2 + j)' equal to zero and attempt to solve: Simplifying 2 + j = 0 Solving 2 + j = 0 Move all terms containing j to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + j = 0 + -2 Combine like terms: 2 + -2 = 0 0 + j = 0 + -2 j = 0 + -2 Combine like terms: 0 + -2 = -2 j = -2 Simplifying j = -2

Solution

j = {0, -2}

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