7j-7=3(j-1)

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Solution for 7j-7=3(j-1) equation: 



7j-7=3(j-1)

We move all terms to the left:

7j-7-(3(j-1))=0



We calculate terms in parentheses: -(3(j-1)), so:

3(j-1)

We multiply parentheses

3j-3

Back to the equation:

-(3j-3)



We get rid of parentheses

7j-3j+3-7=0

We add all the numbers together, and all the variables

4j-4=0

We move all terms containing j to the left, all other terms to the right

4j=4

j=4/4

j=1

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