7k+1+3k+5=2(4k+3)

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Solution for 7k+1+3k+5=2(4k+3) equation: 



7k+1+3k+5=2(4k+3)

We move all terms to the left:

7k+1+3k+5-(2(4k+3))=0

We add all the numbers together, and all the variables

10k-(2(4k+3))+6=0



We calculate terms in parentheses: -(2(4k+3)), so:

2(4k+3)

We multiply parentheses

8k+6

Back to the equation:

-(8k+6)



We get rid of parentheses

10k-8k-6+6=0

We add all the numbers together, and all the variables

2k=0

k=0/2

k=0

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