7k-52=2(7/2k+30

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Solution for 7k-52=2(7/2k+30 equation: 



7k-52=2(7/2k+30

We move all terms to the left:

7k-52-(2(7/2k+30)=0



Domain of the equation: 2k+30)-52!=0

k∈R



We multiply all the terms by the denominator


7k*2k+30)-52-(2(7=0

We add all the numbers together, and all the variables

7k*2k=0

Wy multiply elements

14k^2=0

a = 14; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·14·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$k=\frac{-b}{2a}=\frac{0}{28}=0$

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