7log(3x)+elog(5x)=15

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Solution for 7log(3x)+elog(5x)=15 equation:


Simplifying
7log(3x) + elog(5x) = 15

Remove parenthesis around (3x)
7glo * 3x + elog(5x) = 15

Reorder the terms for easier multiplication:
7 * 3glo * x + elog(5x) = 15

Multiply 7 * 3
21glo * x + elog(5x) = 15

Multiply glo * x
21glox + elog(5x) = 15

Remove parenthesis around (5x)
21glox + eglo * 5x = 15

Reorder the terms for easier multiplication:
21glox + 5eglo * x = 15

Multiply eglo * x
21glox + 5eglox = 15

Reorder the terms:
5eglox + 21glox = 15

Solving
5eglox + 21glox = 15

Solving for variable 'e'.

Move all terms containing e to the left, all other terms to the right.

Add '-21glox' to each side of the equation.
5eglox + 21glox + -21glox = 15 + -21glox

Combine like terms: 21glox + -21glox = 0
5eglox + 0 = 15 + -21glox
5eglox = 15 + -21glox

Divide each side by '5glox'.
e = 3g-1l-1o-1x-1 + -4.2

Simplifying
e = 3g-1l-1o-1x-1 + -4.2

Reorder the terms:
e = -4.2 + 3g-1l-1o-1x-1

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