7m(m+5)=56

Solution for 7m(m+5)=56 equation:

7m(m+5)=56

We move all terms to the left:

7m(m+5)-(56)=0

We multiply parentheses

7m^2+35m-56=0

a = 7; b = 35; c = -56;
Δ = b2-4ac
Δ = 352-4·7·(-56)
Δ = 2793
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2793}=\sqrt{49*57}=\sqrt{49}*\sqrt{57}=7\sqrt{57}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35)-7\sqrt{57}}{2*7}=\frac{-35-7\sqrt{57}}{14}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35)+7\sqrt{57}}{2*7}=\frac{-35+7\sqrt{57}}{14}
$