7m(m+6)=0

Solution for 7m(m+6)=0 equation:

7m(m+6)=0

We multiply parentheses

7m^2+42m=0

a = 7; b = 42; c = 0;
Δ = b2-4ac
Δ = 422-4·7·0
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(42)-42}{2*7}=\frac{-84}{14}
=-6
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(42)+42}{2*7}=\frac{0}{14}
=0
$