7m+1+3m=2(4m+5)+1

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Solution for 7m+1+3m=2(4m+5)+1 equation: 



7m+1+3m=2(4m+5)+1

We move all terms to the left:

7m+1+3m-(2(4m+5)+1)=0

We add all the numbers together, and all the variables

10m-(2(4m+5)+1)+1=0



We calculate terms in parentheses: -(2(4m+5)+1), so:

2(4m+5)+1

We multiply parentheses

8m+10+1

We add all the numbers together, and all the variables

8m+11

Back to the equation:

-(8m+11)



We get rid of parentheses

10m-8m-11+1=0

We add all the numbers together, and all the variables

2m-10=0

We move all terms containing m to the left, all other terms to the right

2m=10

m=10/2

m=5

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