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7m+2m(5-3)=66
We move all terms to the left:
7m+2m(5-3)-(66)=0
We add all the numbers together, and all the variables
7m+2m2-66=0
We add all the numbers together, and all the variables
2m^2+7m-66=0
a = 2; b = 7; c = -66;
Δ = b2-4ac
Δ = 72-4·2·(-66)
Δ = 577
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{577}}{2*2}=\frac{-7-\sqrt{577}}{4} $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{577}}{2*2}=\frac{-7+\sqrt{577}}{4} $
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