7m-(2+m)=-(m-4)

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Solution for 7m-(2+m)=-(m-4) equation: 



7m-(2+m)=-(m-4)

We move all terms to the left:

7m-(2+m)-(-(m-4))=0

We add all the numbers together, and all the variables

7m-(m+2)-(-(m-4))=0

We get rid of parentheses

7m-m-(-(m-4))-2=0



We calculate terms in parentheses: -(-(m-4)), so:

-(m-4)

We get rid of parentheses

-m+4

We add all the numbers together, and all the variables

-1m+4

Back to the equation:

-(-1m+4)



We add all the numbers together, and all the variables

6m-(-1m+4)-2=0

We get rid of parentheses

6m+1m-4-2=0

We add all the numbers together, and all the variables

7m-6=0

We move all terms containing m to the left, all other terms to the right

7m=6

m=6/7

m=6/7

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