7m-(2+m)=5-(m-4)

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Solution for 7m-(2+m)=5-(m-4) equation:



7m-(2+m)=5-(m-4)
We move all terms to the left:
7m-(2+m)-(5-(m-4))=0
We add all the numbers together, and all the variables
7m-(m+2)-(5-(m-4))=0
We get rid of parentheses
7m-m-(5-(m-4))-2=0
We calculate terms in parentheses: -(5-(m-4)), so:
5-(m-4)
determiningTheFunctionDomain -(m-4)+5
We get rid of parentheses
-m+4+5
We add all the numbers together, and all the variables
-1m+9
Back to the equation:
-(-1m+9)
We add all the numbers together, and all the variables
6m-(-1m+9)-2=0
We get rid of parentheses
6m+1m-9-2=0
We add all the numbers together, and all the variables
7m-11=0
We move all terms containing m to the left, all other terms to the right
7m=11
m=11/7
m=1+4/7

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