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7m^2+18m+8=0
a = 7; b = 18; c = +8;
Δ = b2-4ac
Δ = 182-4·7·8
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{100}=10$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-10}{2*7}=\frac{-28}{14} =-2 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+10}{2*7}=\frac{-8}{14} =-4/7 $
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