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7m^2-12m+5=0
a = 7; b = -12; c = +5;
Δ = b2-4ac
Δ = -122-4·7·5
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-2}{2*7}=\frac{10}{14} =5/7 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+2}{2*7}=\frac{14}{14} =1 $
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