7n+3-4(2n-1)+n=8(n-5)-(3n-4)-29

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Solution for 7n+3-4(2n-1)+n=8(n-5)-(3n-4)-29 equation: 



7n+3-4(2n-1)+n=8(n-5)-(3n-4)-29

We move all terms to the left:

7n+3-4(2n-1)+n-(8(n-5)-(3n-4)-29)=0

We add all the numbers together, and all the variables

8n-4(2n-1)-(8(n-5)-(3n-4)-29)+3=0

We multiply parentheses

8n-8n-(8(n-5)-(3n-4)-29)+4+3=0



We calculate terms in parentheses: -(8(n-5)-(3n-4)-29), so:

8(n-5)-(3n-4)-29

We multiply parentheses

8n-(3n-4)-40-29

We get rid of parentheses

8n-3n+4-40-29

We add all the numbers together, and all the variables

5n-65

Back to the equation:

-(5n-65)



We add all the numbers together, and all the variables

-(5n-65)+7=0

We get rid of parentheses

-5n+65+7=0

We add all the numbers together, and all the variables

-5n+72=0

We move all terms containing n to the left, all other terms to the right

-5n=-72

n=-72/-5

n=14+2/5

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