7n+4(3n+3)=(n-5)-4n

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Solution for 7n+4(3n+3)=(n-5)-4n equation:



7n+4(3n+3)=(n-5)-4n
We move all terms to the left:
7n+4(3n+3)-((n-5)-4n)=0
We multiply parentheses
7n+12n-((n-5)-4n)+12=0
We calculate terms in parentheses: -((n-5)-4n), so:
(n-5)-4n
We add all the numbers together, and all the variables
-4n+(n-5)
We get rid of parentheses
-4n+n-5
We add all the numbers together, and all the variables
-3n-5
Back to the equation:
-(-3n-5)
We add all the numbers together, and all the variables
19n-(-3n-5)+12=0
We get rid of parentheses
19n+3n+5+12=0
We add all the numbers together, and all the variables
22n+17=0
We move all terms containing n to the left, all other terms to the right
22n=-17
n=-17/22
n=-17/22

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