7n-2=7(3-5)-3(n+7)

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Solution for 7n-2=7(3-5)-3(n+7) equation: 



7n-2=7(3-5)-3(n+7)

We move all terms to the left:

7n-2-(7(3-5)-3(n+7))=0

We add all the numbers together, and all the variables

7n-(7(-2)-3(n+7))-2=0



We calculate terms in parentheses: -(7(-2)-3(n+7)), so:

7(-2)-3(n+7)

determiningTheFunctionDomain
-3(n+7)+7(-2)

We add all the numbers together, and all the variables

-3(n+7)-14

We multiply parentheses

-3n-21-14

We add all the numbers together, and all the variables

-3n-35

Back to the equation:

-(-3n-35)



We get rid of parentheses

7n+3n+35-2=0

We add all the numbers together, and all the variables

10n+33=0

We move all terms containing n to the left, all other terms to the right

10n=-33

n=-33/10

n=-3+3/10

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