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7n^2-10n-8=0
a = 7; b = -10; c = -8;
Δ = b2-4ac
Δ = -102-4·7·(-8)
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{324}=18$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-18}{2*7}=\frac{-8}{14} =-4/7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+18}{2*7}=\frac{28}{14} =2 $
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