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7n^2-43n=-40
We move all terms to the left:
7n^2-43n-(-40)=0
We add all the numbers together, and all the variables
7n^2-43n+40=0
a = 7; b = -43; c = +40;
Δ = b2-4ac
Δ = -432-4·7·40
Δ = 729
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{729}=27$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-27}{2*7}=\frac{16}{14} =1+1/7 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+27}{2*7}=\frac{70}{14} =5 $
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