7p+(3p+4)=(-2)(2p-1)+10

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Solution for 7p+(3p+4)=(-2)(2p-1)+10 equation:



7p+(3p+4)=(-2)(2p-1)+10
We move all terms to the left:
7p+(3p+4)-((-2)(2p-1)+10)=0
We get rid of parentheses
7p+3p-((-2)(2p-1)+10)+4=0
We multiply parentheses ..
7p+3p-((-4p+2)+10)+4=0
We calculate terms in parentheses: -((-4p+2)+10), so:
(-4p+2)+10
We get rid of parentheses
-4p+2+10
We add all the numbers together, and all the variables
-4p+12
Back to the equation:
-(-4p+12)
We add all the numbers together, and all the variables
10p-(-4p+12)+4=0
We get rid of parentheses
10p+4p-12+4=0
We add all the numbers together, and all the variables
14p-8=0
We move all terms containing p to the left, all other terms to the right
14p=8
p=8/14
p=4/7

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