7p+(3p+4)=(-2)(2p-1)+10

Solution for 7p+(3p+4)=(-2)(2p-1)+10 equation:

7p+(3p+4)=(-2)(2p-1)+10

We move all terms to the left:

7p+(3p+4)-((-2)(2p-1)+10)=0

We get rid of parentheses

7p+3p-((-2)(2p-1)+10)+4=0

We multiply parentheses ..

7p+3p-((-4p+2)+10)+4=0


We calculate terms in parentheses: -((-4p+2)+10), so:

(-4p+2)+10

We get rid of parentheses

-4p+2+10

We add all the numbers together, and all the variables

-4p+12

Back to the equation:

-(-4p+12)


We add all the numbers together, and all the variables

10p-(-4p+12)+4=0

We get rid of parentheses

10p+4p-12+4=0

We add all the numbers together, and all the variables

14p-8=0

We move all terms containing p to the left, all other terms to the right

14p=8

p=8/14

p=4/7