7p+5=3p2

Solution for 7p+5=3p2 equation:

7p+5=3p^2

We move all terms to the left:

7p+5-(3p^2)=0

determiningTheFunctionDomain
-3p^2+7p+5=0

a = -3; b = 7; c = +5;
Δ = b2-4ac
Δ = 72-4·(-3)·5
Δ = 109
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{109}}{2*-3}=\frac{-7-\sqrt{109}}{-6}
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{109}}{2*-3}=\frac{-7+\sqrt{109}}{-6}
$