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7p+5=3p^2
We move all terms to the left:
7p+5-(3p^2)=0
determiningTheFunctionDomain -3p^2+7p+5=0
a = -3; b = 7; c = +5;
Δ = b2-4ac
Δ = 72-4·(-3)·5
Δ = 109
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{109}}{2*-3}=\frac{-7-\sqrt{109}}{-6} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{109}}{2*-3}=\frac{-7+\sqrt{109}}{-6} $
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