7p-(3p+4)=-2(2p-2)+10

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Solution for 7p-(3p+4)=-2(2p-2)+10 equation: 



7p-(3p+4)=-2(2p-2)+10

We move all terms to the left:

7p-(3p+4)-(-2(2p-2)+10)=0

We get rid of parentheses

7p-3p-(-2(2p-2)+10)-4=0



We calculate terms in parentheses: -(-2(2p-2)+10), so:

-2(2p-2)+10

We multiply parentheses

-4p+4+10

We add all the numbers together, and all the variables

-4p+14

Back to the equation:

-(-4p+14)



We add all the numbers together, and all the variables

4p-(-4p+14)-4=0

We get rid of parentheses

4p+4p-14-4=0

We add all the numbers together, and all the variables

8p-18=0

We move all terms containing p to the left, all other terms to the right

8p=18

p=18/8

p=2+1/4

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