7p-3(p+4)=2(2p-1)-10

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Solution for 7p-3(p+4)=2(2p-1)-10 equation:


Simplifying
7p + -3(p + 4) = 2(2p + -1) + -10

Reorder the terms:
7p + -3(4 + p) = 2(2p + -1) + -10
7p + (4 * -3 + p * -3) = 2(2p + -1) + -10
7p + (-12 + -3p) = 2(2p + -1) + -10

Reorder the terms:
-12 + 7p + -3p = 2(2p + -1) + -10

Combine like terms: 7p + -3p = 4p
-12 + 4p = 2(2p + -1) + -10

Reorder the terms:
-12 + 4p = 2(-1 + 2p) + -10
-12 + 4p = (-1 * 2 + 2p * 2) + -10
-12 + 4p = (-2 + 4p) + -10

Reorder the terms:
-12 + 4p = -2 + -10 + 4p

Combine like terms: -2 + -10 = -12
-12 + 4p = -12 + 4p

Add '12' to each side of the equation.
-12 + 12 + 4p = -12 + 12 + 4p

Combine like terms: -12 + 12 = 0
0 + 4p = -12 + 12 + 4p
4p = -12 + 12 + 4p

Combine like terms: -12 + 12 = 0
4p = 0 + 4p
4p = 4p

Add '-4p' to each side of the equation.
4p + -4p = 4p + -4p

Combine like terms: 4p + -4p = 0
0 = 4p + -4p

Combine like terms: 4p + -4p = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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