7p2-5p-2=0

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Solution for 7p2-5p-2=0 equation: 



7p^2-5p-2=0

a = 7; b = -5; c = -2;
Δ = b2-4ac
Δ = -52-4·7·(-2)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{81}=9$


$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-9}{2*7}=\frac{-4}{14}
=-2/7
$


$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+9}{2*7}=\frac{14}{14}
=1
$

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