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7p^2-5p-9=0
a = 7; b = -5; c = -9;
Δ = b2-4ac
Δ = -52-4·7·(-9)
Δ = 277
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{277}}{2*7}=\frac{5-\sqrt{277}}{14} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{277}}{2*7}=\frac{5+\sqrt{277}}{14} $
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