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7p^2-6p-16=0
a = 7; b = -6; c = -16;
Δ = b2-4ac
Δ = -62-4·7·(-16)
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{484}=22$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-22}{2*7}=\frac{-16}{14} =-1+1/7 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+22}{2*7}=\frac{28}{14} =2 $
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