7q-(3q+13)=7-(4q-5)

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Solution for 7q-(3q+13)=7-(4q-5) equation: 



7q-(3q+13)=7-(4q-5)

We move all terms to the left:

7q-(3q+13)-(7-(4q-5))=0

We get rid of parentheses

7q-3q-(7-(4q-5))-13=0



We calculate terms in parentheses: -(7-(4q-5)), so:

7-(4q-5)

determiningTheFunctionDomain
-(4q-5)+7

We get rid of parentheses

-4q+5+7

We add all the numbers together, and all the variables

-4q+12

Back to the equation:

-(-4q+12)



We add all the numbers together, and all the variables

4q-(-4q+12)-13=0

We get rid of parentheses

4q+4q-12-13=0

We add all the numbers together, and all the variables

8q-25=0

We move all terms containing q to the left, all other terms to the right

8q=25

q=25/8

q=3+1/8

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