7q-3(3q+6)=7(6+q)

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Solution for 7q-3(3q+6)=7(6+q) equation: 



7q-3(3q+6)=7(6+q)

We move all terms to the left:

7q-3(3q+6)-(7(6+q))=0

We add all the numbers together, and all the variables

7q-3(3q+6)-(7(q+6))=0

We multiply parentheses

7q-9q-(7(q+6))-18=0



We calculate terms in parentheses: -(7(q+6)), so:

7(q+6)

We multiply parentheses

7q+42

Back to the equation:

-(7q+42)



We add all the numbers together, and all the variables

-2q-(7q+42)-18=0

We get rid of parentheses

-2q-7q-42-18=0

We add all the numbers together, and all the variables

-9q-60=0

We move all terms containing q to the left, all other terms to the right

-9q=60

q=60/-9

q=-6+2/3

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